CC:=C;
Y10:=CC+10;
Y20:=CC+20;
Y30:=CC+30;
每次C變動時,同樣加一次代入KD公式.以求得K10,K20,K30之值.
而新的成交價(C)一顯出,本次的成交價(C)就成前次的成交價(C) .這樣一直循環著.今要本次C 的K值先比最小,再和前次C 的K值比最小
前次C:=MIN(K10,K20),K30);
本次C:=MIN(K10,K20),K30);
請幫忙指導 謝謝

KD公式 <<<-----???

您定義不清唷

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INPUT:N(5):
CC:=O;
Y1:=CC+1*N; Y2:=CC+2*N; Y3:=CC+3*N; Y3:=CC+4*N;

RSV1:=(Y1-LLV(LOW,9))/(HHV(HIGH,9)-LLV(LOW,9))*100;
K1:=(RSV1+2*REF(K,1))/3;
RSV2:=(Y2-LLV(LOW,9))/(HHV(HIGH,9)-LLV(LOW,9))*100;
K2:=(RSV2+2*REF(K,1))/3;
RSV3:=(Y3-LLV(LOW,9))/(HHV(HIGH,9)-LLV(LOW,9))*100;
K3:=(RSV3+2*REF(K,1))/3;
RSV4:=(Y4-LLV(LOW,9))/(HHV(HIGH,9)-LLV(LOW,9))*100;
K4:=(RSV4+2*REF(K,1))/3;

A1:=K1>=D; A2:=K2>=D; A3:=K3>=D; A4:=K4>=D;
B1:=K1<D; B2:=K2<D; B3:=K3<D; B4:=K4<D;

A11:=IF(ZA AND A1,K1-D,0); A22:=IF(ZA AND A2,K2-D,0); A33:=IF(ZA AND A3,K3-D,0); A44:=IF(ZA AND A4,K4-D,0);

CMI:=MIN(MIN(MIN(A11,A22),A33),A44);
希望
1:一更新, 本筆CM1就變成前一筆CM1
2:本筆CM1與前一筆CM1一直循環著相比小
請幫忙指導 謝謝

引用:

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最初由 mori868 發表
INPUT:N(5):
CC:=O;
Y1:=CC+1*N; Y2:=CC+2*N; Y3:=CC+3*N; Y3:=CC+4*N;

RSV1:=(Y1-LLV(LOW,9))/(HHV(HIGH,9)-LLV(LOW,9))*100;
K1:=(RSV1+2*REF(K,1))/3;
RSV2:=(Y2-LLV(LOW,9))/(HHV(HIGH,9)-LLV(LOW,9))*100;
K2:=(RSV2+2*REF(K,1))/3;
RSV3:=(Y3-LLV(LOW,9))/(HHV(HIGH,9)-LLV(LOW,9))*100;
K3:=(RSV3+2*REF(K,1))/3;
RSV4:=(Y4-LLV(LOW,9))/(HHV(HIGH,9)-LLV(LOW,9))*100;
K4:=(RSV4+2*REF(K,1))/3;

A1:=K1>=D; A2:=K2>=D; A3:=K3>=D; A4:=K4>=D;
B1:=K1<D; B2:=K2<D; B3:=K3<D; B4:=K4<D;

A11:=IF(ZA AND A1,K1-D,0); A22:=IF(ZA AND A2,K2-D,0); A33:=IF(ZA AND A3,K3-D,0); A44:=IF(ZA AND A4,K4-D,0);

CMI:=MIN(MIN(MIN(A11,A22),A33),A44);
希望
1:一更新, 本筆CM1就變成前一筆CM1
2:本筆CM1與前一筆CM1一直循環著相比小
請幫忙指導 謝謝

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掐頭去尾 沒頭沒腦的 看了費神
要請人協助 拜託 給個完整點的內容
再不說個具體需求
大概沒有人閑到玩猜猜看的遊戲

等您二次修正再看看吧

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引用:

---

最初由 peter109 發表
掐頭去尾 沒頭沒腦的 看了費神
要請人協助 拜託 給個完整點的內容
再不說個具體需求
大概沒有人閑到玩猜猜看的遊戲

等您二次修正再看看吧

---

對高手來說可以直接排序後求出答案
初學程式的我 卻需要 ZA 和 D 的定義!!??

未經測試的結果 無法判定是否正確

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RSV:=(CLOSE-LLV(LOW,9))/(HHV(HIGH,9)-LLV(LOW,9))*100;
K:=SMA(RSV,3,1);
D:=SMA(K,3,1);

A:=CROSS(K,D);
B:=CROSS(D,K);

ZA:=BARSLAST(A);
ZB:=BARSLAST(B);

1:每次 C 改變時,皆要代入公式,而求得最小值CMI.
2:希望
今C所求得最小值CMI與前筆C所求得最小值CMI能再比最小
請教今最小值CMI與前筆最小值CMI,如何求得兩筆的最小值,這樣如何編寫而已

INPUT:N(5):
CC:=C;
Y1:=CC+1*N; Y2:=CC+2*N; Y3:=CC+3*N; Y3:=CC+4*N;

RSV1:=(Y1-LLV(LOW,9))/(HHV(HIGH,9)-LLV(LOW,9))*100;
K1:=(RSV1+2*REF(K,1))/3;
RSV2:=(Y2-LLV(LOW,9))/(HHV(HIGH,9)-LLV(LOW,9))*100;
K2:=(RSV2+2*REF(K,1))/3;
RSV3:=(Y3-LLV(LOW,9))/(HHV(HIGH,9)-LLV(LOW,9))*100;
K3:=(RSV3+2*REF(K,1))/3;
RSV4:=(Y4-LLV(LOW,9))/(HHV(HIGH,9)-LLV(LOW,9))*100;
K4:=(RSV4+2*REF(K,1))/3;

A1:=K1>=D; A2:=K2>=D; A3:=K3>=D; A4:=K4>=D;
B1:=K1<D; B2:=K2<D; B3:=K3<D; B4:=K4<D;

A11:=IF(ZA AND A1,K1-D,0); A22:=IF(ZA AND A2,K2-D,0); A33:=IF(ZA AND A3,K3-D,0); A44:=IF(ZA AND A4,K4-D,0);

CMI:=MIN(MIN(MIN(A11,A22),A33),A44);

看不出您目前公式的實戰性

如果只是比較
min(cmi,ref(cmi,1))

今最小值CMI = CMI 公式中不是已經求出了嗎

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