n,14 / m,6

TR:=SMA(MAX(MAX(HIGH-LOW,ABS(HIGH-REF(CLOSE,1))),ABS(LOW-REF(CLOSE,1))),N,1);
HD:=HIGH-REF(HIGH,1);
LD:=REF(LOW,1)-LOW;
DMP:=SMA(IF(HD>0 AND HD>LD,HD,0),N,1);
DMM:=SMA(IF(LD>0 AND LD>HD,LD,0),N,1);
PDI:=DMP*100/TR;
MDI:=DMM*100/TR;
ADX:=SMA(ABS(MDI-PDI)/(MDI+PDI)*100,M,1);

1.)如何預估 pdi 與dmi 交叉的點位?
2.)如何預估 adx 與dmi 交叉的點位?

引用:

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最初由 jery3308 發表
n,14 / m,6

TR:=SMA(MAX(MAX(HIGH-LOW,ABS(HIGH-REF(CLOSE,1))),ABS(LOW-REF(CLOSE,1))),N,1);
HD:=HIGH-REF(HIGH,1);
LD:=REF(LOW,1)-LOW;
DMP:=SMA(IF(HD>0 AND HD>LD,HD,0),N,1);
DMM:=SMA(IF(LD>0 AND LD>HD,LD,0),N,1);
PDI:=DMP*100/TR;
MDI:=DMM*100/TR;
ADX:=SMA(ABS(MDI-PDI)/(MDI+PDI)*100,M,1);

1.)如何預估 pdi 與dmi 交叉的點位?
2.)如何預估 adx 與dmi 交叉的點位?

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